Search Answers
Search Crossword Answers
1985 U.S. Open winner Mandlikova Crossword Clue
Here is the answer for the crossword clue 1985 U.S. Open winner Mandlikova . We have found 40 possible answers for this clue in our database. Among them, one solution stands out with a 98% match which has a length of 4 letters. We think the likely answer to this clue is HANA.
Love the NYT Mini? Try our Mini. You'll like our free daily Mini Crossword.
Fresh puzzles every day, no paywall.
Crossword Answer For 1985 U.S. Open winner Mandlikova:
You can click on thetiles to reveal letter by letter before uncovering the full solution.
40 Potential Answers:
| Rank | Answer | Length | Source | Date |
|---|---|---|---|---|
| 98% | HANA 1985 U.S. Open winner Mandlikova | (4) | ||
| 71% | CELIE Whoopi's role in 1985's "The Color Purple" | (5) | New York Times | Oct 6, 2025 |
| 67% | SRS "r u ___?" ("u mean it?") | (3) | USA Today | Oct 13, 2025 |
| 67% | ANDY & 9D US golfer; 1978 and 1985 US Open Championship winner (4,5) | (4) | Mirror Quiz | Aug 2, 2025 |
| 64% | RAMBO 1985 Stallone film | (5) | Commuter | Oct 28, 2025 |
| 64% | UNIT The "U" in ICU | (4) | ||
| 64% | WYD "u up?" | (3) | The Atlantic | Oct 1, 2025 |
| 64% | LLOYD French Open winner of 1985 | (5) | ||
| 61% | OBVI "did u not know that?" | (4) | The Atlantic | Nov 6, 2025 |
| 61% | UNDO Open | (4) | The Telegraph Cross Atlantic | Nov 5, 2025 |
Fresh Clues From Recent Puzzles
Your Crossword Clues FAQ Guide
We found 40 solutions for 1985 U.S. Open winner Mandlikova. The top solutions are determined by popularity, ratings and frequency of searches. The most likely answer for the clue is HANA.
With crossword-solver.io you will find 40 solutions. We use historic puzzles to find the best matches for your question. We add many new clues on a daily basis.
With our crossword solver search engine you have access to over 7 million clues. You can narrow down the possible answers by specifying the number of letters it contains. We found more than 40 answers for 1985 U.S. Open winner Mandlikova.