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___ Vonn, former alpine ski racer who was the first American woman to win an Olympic gold in downhill skiing Crossword Clue
Here is the answer for the crossword clue ___ Vonn, former alpine ski racer who was the first American woman to win an Olympic gold in downhill skiing . We have found 40 possible answers for this clue in our database. Among them, one solution stands out with a 98% match which has a length of 7 letters. We think the likely answer to this clue is LINDSEY.
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Crossword Answer For ___ Vonn, former alpine ski racer who was the first American woman to win an Olympic gold in downhill skiing:
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40 Potential Answers:
| Rank | Answer | Length | Source | Date |
|---|---|---|---|---|
| 98% | LINDSEY ___ Vonn, former alpine ski racer who was the first American woman to win an Olympic gold in downhill skiing | (7) | ||
| 6% | SLALOM Alpine skiing discipline | (6) | USA Today | May 31, 2026 |
| 5% | UAL "Friendly skies" co. | (3) | Eugene Sheffer | Aug 20, 2026 |
| 5% | POWDER Snow for skiing | (6) | Wall Street Journal | Aug 19, 2026 |
| 5% | ASPEN Colorado ski town | (5) | USA Today | Aug 19, 2026 |
| 5% | ALTA Utah skiing destination | (4) | New York Times | Aug 18, 2026 |
| 5% | SLALOMS Ski races with gates | (7) | LA Times Daily | Aug 17, 2026 |
| 5% | POLES Ski equipment | (5) | USA Today | Aug 11, 2026 |
| 5% | TBAR Ski lift | (4) | LA Times Daily | Aug 9, 2026 |
| 5% | UFO Bigfoot of the skies: abbr. | (3) | The Atlantic | Aug 8, 2026 |
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We found 40 solutions for ___ Vonn, former alpine ski racer who was the first American woman to win an Olympic gold in downhill skiing. The top solutions are determined by popularity, ratings and frequency of searches. The most likely answer for the clue is LINDSEY.
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With our crossword solver search engine you have access to over 7 million clues. You can narrow down the possible answers by specifying the number of letters it contains. We found more than 40 answers for ___ Vonn, former alpine ski racer who was the first American woman to win an Olympic gold in downhill skiing.