Search Answers
Search Crossword Answers
Alexander. Russian author of the play Too Clever By Half (9) Crossword Clue
Here is the answer for the crossword clue Alexander. Russian author of the play Too Clever By Half (9) . We have found 40 possible answers for this clue in our database. Among them, one solution stands out with a 98% match which has a length of 9 letters. We think the likely answer to this clue is OSTROVSKY.
Crossword Answer For Alexander. Russian author of the play Too Clever By Half (9):
You can click on thetiles to reveal letter by letter before uncovering the full solution.
40 Potential Answers:
| Rank | Answer | Length | Source | Date |
|---|---|---|---|---|
| 98% | OSTROVSKY Alexander. Russian author of the play Too Clever By Half (9) | (9) | ||
| 6% | SMART Clever | (5) | The Telegraph Quick | Aug 7, 2025 |
| 6% | FLY A six-footer - clever, too! | (3) | ||
| 6% | SLY Too clever by half | (3) | ||
| 5% | TRUTH Half-__ | (5) | Newsday | Sep 6, 2025 |
| 5% | BLINI Russian pancakes | (5) | New York Times | Sep 1, 2025 |
| 5% | TSAR Russian emperor | (4) | The Telegraph Cross Atlantic | Aug 28, 2025 |
| 5% | TRAMS Flipping clever vehicles | (5) | The Telegraph Cryptic | Aug 26, 2025 |
| 5% | NYET Russian "no" | (4) | New York Times | Aug 24, 2025 |
| 5% | OVERLY Too | (6) | LA Times Daily | Aug 21, 2025 |
Fresh Clues From Recent Puzzles
Your Crossword Clues FAQ Guide
We found 40 solutions for Alexander. Russian author of the play Too Clever By Half (9). The top solutions are determined by popularity, ratings and frequency of searches. The most likely answer for the clue is OSTROVSKY.
With crossword-solver.io you will find 40 solutions. We use historic puzzles to find the best matches for your question. We add many new clues on a daily basis.
With our crossword solver search engine you have access to over 7 million clues. You can narrow down the possible answers by specifying the number of letters it contains. We found more than 40 answers for Alexander. Russian author of the play Too Clever By Half (9).