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Jacob ...., New Zealand Test cricketer who made 101 against England at Lord's in 2008 (4) Crossword Clue
Here is the answer for the crossword clue Jacob ...., New Zealand Test cricketer who made 101 against England at Lord's in 2008 (4) . We have found 40 possible answers for this clue in our database. Among them, one solution stands out with a 98% match which has a length of 4 letters. We think the likely answer to this clue is ORAM.
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Crossword Answer For Jacob ...., New Zealand Test cricketer who made 101 against England at Lord's in 2008 (4):
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40 Potential Answers:
| Rank | Answer | Length | Source | Date |
|---|---|---|---|---|
| 98% | ORAM Jacob ...., New Zealand Test cricketer who made 101 against England at Lord's in 2008 (4) | (4) | ||
| 82% | JACOB New Zealand Test cricketer who made 101 against England at Lord's in 2008 (5,4) | (5) | ||
| 80% | ASTLE N J -, New Zealand Test cricketer who made 222 against England in Christchurch in 2002 (5) | (5) | Mirror Quiz | Mar 9, 2026 |
| 77% | REEVE D A -, cricketer; 1992 England Test debutant against New Zealand in Christchurch (5) | (5) | Mirror Quiz | Feb 23, 2026 |
| 65% | NAIR K K -, India Test cricketer who made an unbeaten 303 against England in Chennai in 2016 (4) | (4) | Mirror Quiz | Feb 16, 2026 |
| 63% | MASSIE R A L -, Australia Test cricketer who took 8-84 and 8-53 against England at Lord's in 1972 (6) | (6) | Mirror Quiz | Feb 6, 2026 |
| 63% | KIWI New Zealander | (4) | New York Times | Feb 1, 2026 |
| 63% | ELWORTHY S -, South Africa cricketer; 1998 Test debutant against England in Nottingham (8) | (8) | Mirror Quiz | Dec 4, 2025 |
| 63% | KNOTT A P E -, England Test cricketer who hit 101 against New Zealand in Auckland in 1971 | (5) | Mirror Quiz | Oct 15, 2024 |
| 60% | BROAD S C J -, England Test cricketer who took 5-85 against West Indies in Kingston in 2009 (5) | (5) | Mirror Quiz | Feb 9, 2026 |
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We found 40 solutions for Jacob ...., New Zealand Test cricketer who made 101 against England at Lord's in 2008 (4). The top solutions are determined by popularity, ratings and frequency of searches. The most likely answer for the clue is ORAM.
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