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Mark -, 1976 Australian Open singles tennis championship winner (9) Crossword Clue
Here is the answer for the crossword clue Mark -, 1976 Australian Open singles tennis championship winner (9) featured in Mirror Quiz puzzle on April 29, 2026. We have found 40 possible answers for this clue in our database. Among them, one solution stands out with a 98% match which has a length of 9 letters. We think the likely answer to this clue is EDMONDSON.
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Crossword Answer For Mark -, 1976 Australian Open singles tennis championship winner (9):
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40 Potential Answers:
| Rank | Answer | Length | Source | Date |
|---|---|---|---|---|
| 98% | EDMONDSON Mark -, 1976 Australian Open singles tennis championship winner (9) | (9) | Mirror Quiz | Apr 29, 2026 |
| 8% | KRIEK Johan -, 1981 and 1982 Australian Open singles tennis championship winner (5) | (5) | Mirror Quiz | Apr 27, 2026 |
| 8% | LINA 2014 Australian Open women's singles tennis championship winner (2,2) | (4) | Mirror Quiz | Apr 15, 2026 |
| 8% | LENDL Ivan -, 1989 Australian Open singles tennis championship winner (5) | (5) | Mirror Quiz | Apr 9, 2026 |
| 7% | HUBER Anke -, 1996 Australian Open singles tennis championship runner-up (5) | (5) | Mirror Quiz | Apr 29, 2026 |
| 7% | STOSUR Samantha -, 2011 US Open singles tennis championship winner (6) | (6) | Mirror Quiz | Apr 10, 2026 |
| 7% | MOYA Carlos -, 1998 French Open singles tennis championship winner (4) | (4) | Mirror Quiz | Apr 4, 2026 |
| 7% | NASTASE Ilie -, 1972 US Open singles tennis championship winner (7) | (7) | Mirror Quiz | Apr 3, 2026 |
| 7% | RIOS Marcelo -, 1998 Australian Open singles tennis championship runner-up (4) | (4) | Mirror Quiz | Mar 22, 2026 |
| 7% | CHANG Michael -, 1989 French Open singles tennis championship winner (5) | (5) | Mirror Quiz | Feb 19, 2026 |
Clues for The Mirror Quiz Puzzle on April 29, 2026
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We found 40 solutions for Mark -, 1976 Australian Open singles tennis championship winner (9). The top solutions are determined by popularity, ratings and frequency of searches. The most likely answer for the clue is EDMONDSON.
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