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Sage, who is this breed of dog, won Best in Show on May 14 at the Westminster Kennel Club's 148th annual dog show Crossword Clue
Here is the answer for the crossword clue Sage, who is this breed of dog, won Best in Show on May 14 at the Westminster Kennel Club's 148th annual dog show . We have found 40 possible answers for this clue in our database. Among them, one solution stands out with a 98% match which has a length of 15 letters. We think the likely answer to this clue is MINIATUREPOODLE.
Crossword Answer For Sage, who is this breed of dog, won Best in Show on May 14 at the Westminster Kennel Club's 148th annual dog show:
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40 Potential Answers:
| Rank | Answer | Length | Source | Date |
|---|---|---|---|---|
| 98% | MINIATUREPOODLE Sage, who is this breed of dog, won Best in Show on May 14 at the Westminster Kennel Club's 148th annual dog show | (15) | ||
| 65% | USA Westminster Kennel Club Dog Show network | (3) | LA Times Daily | Jun 26, 2015 |
| 65% | BREED Westminster Kennel Club Dog Show category | (5) | ||
| 63% | BICHONFRISE Winning breed at the 2018 Westminster Kennel Club Dog Show | (11) | Wall Street Journal | May 11, 2020 |
| 58% | CORGI Dog breed | (5) | The Telegraph Quick | Aug 18, 2025 |
| 56% | LEASH Leader at a dog show? | (5) | ||
| 56% | JUDGE Dog show official | (5) | Newsday | Jul 20, 2025 |
| 55% | ROWLF Muppet Show dog | (5) | Newsday | Jun 27, 2025 |
| 55% | AGILE Like some Westminster Kennel Club Dog Show competitors | (5) | ||
| 53% | LHASA ___ apso (dog breed) | (5) | USA Today | Sep 8, 2025 |
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We found 40 solutions for Sage, who is this breed of dog, won Best in Show on May 14 at the Westminster Kennel Club's 148th annual dog show. The top solutions are determined by popularity, ratings and frequency of searches. The most likely answer for the clue is MINIATUREPOODLE.
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